Find: (2y^3*3x^{-1}y^3)/(3x^2y^4)

Julius Blankenship

Julius Blankenship

Answered question

2022-09-02

Find:
2 y 3 3 x 1 y 3 3 x 2 y 4

Answer & Explanation

Giancarlo Callahan

Giancarlo Callahan

Beginner2022-09-03Added 12 answers

Solution
2 y 3 3 x 1 y 3 3 x 2 y 4 2 y 3 y 3 3 3 x 2 y 4 1 x = 6 y ( 3 + 3 ) 3 x 2 + 1 y 4 6 y 6 3 x 3 y 4 2 y 2 3 x 3

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?