The smaller of two consecutive even integers is five more than one half of the greater. Solve uisng x and x+1 for the equation. Explain each step and find the numbers.

Malik Turner

Malik Turner

Answered question

2022-09-03

The smaller of two consecutive even integers is five more than one half of the greater.
Solve uisng x and x+1 for the equation. Explain each step and find the numbers.

Answer & Explanation

enviroatz0z

enviroatz0z

Beginner2022-09-04Added 12 answers

two consecutive numbers x and x+1
smaller of two consecutive even integersis five more than one half of the greater
x = 5+ (x+1)/2
x-5= (x+1)/2
2x -10 = x+1
x=11 and x+1= 12
Kendra Hudson

Kendra Hudson

Beginner2022-09-05Added 5 answers

x = 1st number
x+1 = 2nd number
x + 1 2 = 1 / 2 the larger number
x + 1 2 + 5 = 5 more than half the larger number
x = x + 1 2 + 5 the smaller number is 5 more than half the larger number
get rid of the fraction by multiplying all terms by 2
2x=x+1+10 combine like terms
2x=x+11 subtract x from each side
x=11
x+1=12
is 11 5 more then half of 12 6+5=11yes

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?