How do you graph f(x)=−3/x using holes, vertical and horizontal asymptotes, x and y intercepts?

tsuyakas1

tsuyakas1

Answered question

2022-09-10

How do you graph f ( x ) = - 3 x using holes, vertical and horizontal asymptotes, x and y intercepts?

Answer & Explanation

Jazmin Bryan

Jazmin Bryan

Beginner2022-09-11Added 12 answers

Set x=0 to solve for y intercept:

f ( x ) = - 3 x

- 3 0 in undefined so no y intercept exists

Set f(x)=y=0 to solve for x intercept(s):

0 = - 3 x

0=−3 is not possible so no x intercept(s) exist.

There are no holes because you cannot cancel any factors with x in them from the denominator.

Set the denominator=0 to solve fo asymptotes:

x=0 so there is a vertical asymptote at y=0.

x ± , f ( x ) 0 so there is a horizontal asymptote at x=0

graph{-3/x [-10, 10, -5, 5]}

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