When a 49 pound weight is attached to a spring, the spring stretches 7 inches. Assume that the length of the spring y varies directly with the weight attached x. Write and solve a direct variation equation to find the length of the spring when a 63 pound weight is attached.

obojeneqk

obojeneqk

Answered question

2022-09-09

When a 49 pound weight is attached to a spring, the spring stretches 7 inches. Assume that the length of the spring y varies directly with the weight attached x. Write and solve a direct variation equation to find the length of the spring when a 63 pound weight is attached.

Answer & Explanation

Skye Hamilton

Skye Hamilton

Beginner2022-09-10Added 14 answers

y and x
y = k x
given for y = 7 in x = 49 pound
7 = k × 49 k = 7 49  pound = 1 7
Now when x=63 ponds
y = 1 7 × 63 = 9  in
Hence length of the spring = 9 inches

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