jatericrimson8b

2022-09-11

A small motor on a fishing boat can move the boat at a rate of 12 mph in calm water. Traveling with the current, the boat can travel 28 mi in the same amount of time it takes to travel 20 mi against the current. Find the rate of the current.

Ashlee Ramos

Beginner2022-09-12Added 20 answers

Let rate of current = x

$$t=\frac{d}{r}\phantom{\rule{0ex}{0ex}}\text{So,}\frac{28}{12+x}=\frac{20}{12-x}\phantom{\rule{0ex}{0ex}}\Rightarrow 7(12-x)=5(12+x)\phantom{\rule{0ex}{0ex}}\Rightarrow 84-7x-60-5x=0\phantom{\rule{0ex}{0ex}}\Rightarrow 12x=24\phantom{\rule{0ex}{0ex}}x=2$$

Rate of current 2 mph

$$t=\frac{d}{r}\phantom{\rule{0ex}{0ex}}\text{So,}\frac{28}{12+x}=\frac{20}{12-x}\phantom{\rule{0ex}{0ex}}\Rightarrow 7(12-x)=5(12+x)\phantom{\rule{0ex}{0ex}}\Rightarrow 84-7x-60-5x=0\phantom{\rule{0ex}{0ex}}\Rightarrow 12x=24\phantom{\rule{0ex}{0ex}}x=2$$

Rate of current 2 mph

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