How do you find the asymptote and graph y=1/(x+3)?

unjulpild9b

unjulpild9b

Answered question

2022-09-23

How do you find the asymptote and graph y = 1 x + 3 ?

Answer & Explanation

embraci4i

embraci4i

Beginner2022-09-24Added 10 answers

y = 1 x + 3
y is defined x - 3
Let's examine y as x approaches −3 from above and from below.
lim x - 3 + 1 x + 3 +
lim x - 3 - 1 x + 3 -
Therefore, y is discontinuous at x=−3 and has a vertical asymptote at that point.
Now consider:
lim x - y = 0 and lim x + y = 0
Hence the x−axis forms a horizontal asymptote.
Therefore, y has a horizontal asymptote at y=0
y is a rectangular hyperbola with the graph below.
graph{1/(x+3) [-7.58, 4.904, -3.4, 2.843]}

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?