jamstavajo

2022-09-03

The doubling period of a bacterial population is 10 minutes. At timet population was 60000.

Find the size of the bacterial population after 3 hours.

Find the size of the bacterial population after 3 hours.

Tristin Durham

Beginner2022-09-04Added 6 answers

exponential growth formula

$$p(t)=90t\phantom{\rule{0ex}{0ex}}t=90,\text{}p(t)=60000\phantom{\rule{0ex}{0ex}}t=80,\text{}p(t)=30000$$

put $$t=80\text{}p(t)=30000\phantom{\rule{0ex}{0ex}}30000={96}^{80}\phantom{\rule{0ex}{0ex}}\frac{60000}{30000}=\frac{{96}^{90}}{{96}^{80}}\phantom{\rule{0ex}{0ex}}2={6}^{10}\phantom{\rule{0ex}{0ex}}6={2}^{1/10}\phantom{\rule{0ex}{0ex}}p(t)=30720000$$

$$p(t)=90t\phantom{\rule{0ex}{0ex}}t=90,\text{}p(t)=60000\phantom{\rule{0ex}{0ex}}t=80,\text{}p(t)=30000$$

put $$t=80\text{}p(t)=30000\phantom{\rule{0ex}{0ex}}30000={96}^{80}\phantom{\rule{0ex}{0ex}}\frac{60000}{30000}=\frac{{96}^{90}}{{96}^{80}}\phantom{\rule{0ex}{0ex}}2={6}^{10}\phantom{\rule{0ex}{0ex}}6={2}^{1/10}\phantom{\rule{0ex}{0ex}}p(t)=30720000$$

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