ladymint0w

2022-10-09

The population of a city t years now is given by

$$P=250000{e}^{0.04t}$$

$$P=250000{e}^{0.04t}$$

Jane Reese

Beginner2022-10-10Added 8 answers

Solved;

$$P=250000{e}^{0.04t}$$

Derivative of $$P=250000{e}^{0.04t}$$

Derivative of $$\Rightarrow 0.4(250000)\phantom{\rule{0ex}{0ex}}\Rightarrow 0.4(250000){e}^{0.4t}\phantom{\rule{0ex}{0ex}}\Rightarrow 0.04(25000){e}^{0.04(3)})\phantom{\rule{0ex}{0ex}}\Rightarrow 0.04(25000){e}^{0.12}\phantom{\rule{0ex}{0ex}}\Rightarrow 11274.96$$

or 11275 people per year

$$P=250000{e}^{0.04t}$$

Derivative of $$P=250000{e}^{0.04t}$$

Derivative of $$\Rightarrow 0.4(250000)\phantom{\rule{0ex}{0ex}}\Rightarrow 0.4(250000){e}^{0.4t}\phantom{\rule{0ex}{0ex}}\Rightarrow 0.04(25000){e}^{0.04(3)})\phantom{\rule{0ex}{0ex}}\Rightarrow 0.04(25000){e}^{0.12}\phantom{\rule{0ex}{0ex}}\Rightarrow 11274.96$$

or 11275 people per year

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