properties of logarithms ln12-ln2=ln6 I checked wolframalpha and it says that ln12-ln2=ln6. How? i tried to do: ln12=ln(2*2*3) which may be 2ln(2*3) (which is probably wrong). I need help. EDIT: Ok, thanks. Actually i could have just searched logarithms properties on google(didn't think about it). Sorry for taking your time.

Bridger Holden

Bridger Holden

Answered question

2022-09-06

properties of logarithms ln 12 ln 2 = ln 6
I checked wolframalpha and it says that ln12-ln2=ln6. How? i tried to do: ln12=ln(2*2*3) which may be 2ln(2*3) (which is probably wrong). I need help.
EDIT: Ok, thanks. Actually i could have just searched logarithms properties on google(didn't think about it). Sorry for taking your time.

Answer & Explanation

Krha77

Krha77

Beginner2022-09-07Added 8 answers

You need to remember that
ln a ln b = ln ( a b )
Applying that here gives you
ln ( 12 ) ln ( 2 ) = ln ( 12 2 ) = ln ( 6 )
Note, alternatively, that we can use the property
ln ( a b ) = ln a + ln b
as well.
ln ( 12 ) = ln ( 2 6 ) = ln ( 2 ) + ln 6
So
ln ( 12 ) ln 2 = ln 2 + ln 6 ln 2 = ln 6
Sonia Rowland

Sonia Rowland

Beginner2022-09-08Added 1 answers

Hint: Use the property
ln x ln y = ln x y .

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?