2022-09-06

A baseball is projected upward from the top of a 448-ft-tall building with an initial velocity of 48 feet per second. The height, h,of the baseball above the ground at any time, t, in seconds, is given by the equation $h\left(t\right)=-16{t}^{2}+48t+448$
a) Find the height after 2 seconds
b) Find the height after 4 seconds
c) Find the time it takes for the baseball to strike the ground

Collin Gilbert

$h\left(t\right)=-16{t}^{2}+48t+448.$
a) Find the height after 2 seconds
$h\left(2\right)=-16\left(2{\right)}^{2}+48\left(2\right)+448=480$
Height after 2 seconds : 480 feet
480 feet
b) Find the height after 4 seconds
$h\left(2\right)=-16\left(4{\right)}^{2}+48\left(4\right)+448=384$
Height after 4 seconds : 384 feet
384 feet
c) Find the time it takes for the baseball to strike the ground.
When the baseball strikes the ground, height is 0.
h(t) = 0

As t = -4 is not a reasonable value for time, it is rejected.
t = 7
Time taken for the baseball to strike the ground : 7 seconds
7 seconds

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