How to solve for k when the area about the x axis and under the graph of the f(x)=1/x from interval x=[2,k] is equal to ln(4)?

caschaillo7

caschaillo7

Answered question

2022-10-17

How to solve for k when the area about the x axis and under the graph of the f ( x ) = 1 x from interval x = [ 2 , k ] is equal to ln ( 4 )?

Answer & Explanation

Kaylee Evans

Kaylee Evans

Beginner2022-10-18Added 20 answers

Notice
2 k 1 x d x = ln 4 = 2 ln 2
This is given. But
2 k 1 x d x = ln k ln 2
Hence,
ln k ln 2 = 2 ln 2 ln k = 3 ln 2 ln k = ln 2 3 k = 2 3 = 8

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