Need help with understanding manipulations on logarithms I cannot understand the result from logarithms manipulations even though I am going over logarithmic properties. I am simply stuck. So here is the problem: n = 2^k => k = log_2n x = 3^k => k = log_3x log_2n = (log_3n)/(log_3 2) log_3x = log_3n^(1.59) I do not understand how we got the last line of the solution! I understand it must be very simple to understand, but I am stuck with it. I will be thankful for help.

Diego Barr

Diego Barr

Answered question

2022-10-17

Need help with understanding manipulations on logarithms
I cannot understand the result from logarithms manipulations even though I am going over logarithmic properties. I am simply stuck. So here is the problem:
n = 2 k k = log 2 n
x = 3 k k = log 3 x
log 2 n = log 3 n log 3 2
log 3 x = log 3 n 1.59
I do not understand how we got the last line of the solution! I understand it must be very simple to understand, but I am stuck with it. I will be thankful for help.

Answer & Explanation

Miah Scott

Miah Scott

Beginner2022-10-18Added 19 answers

log 3 x = log 3 n log 3 2 = 1.59 log 3 n
Because 1 log 3 2 = 1.59 and use that c log a b = log a b c .

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