How do I solve the equation e^(ln(2x+1))= 5x I've tried using natural logs to both sides like.. 2x+1=ln5x But I'm not sure if ln and e^ln cancel out.

ebendasqc

ebendasqc

Answered question

2022-10-27

How do I solve the equation e ln ( 2 x + 1 ) = 5 x?
I've tried using natural logs to both sides like.. 2 x + 1 = ln 5 x But I'm not sure if ln and e ln cancel out.

Answer & Explanation

Kamden Simmons

Kamden Simmons

Beginner2022-10-28Added 10 answers

Yes, the exponential and the logarithm are inverses:
e ln ( s t u f f ) = s t u f f , ln ( e s t u f f ) = s t u f f ,
so that e ln ( 2 x + 1 ) = 2 x + 1
ndevunidt

ndevunidt

Beginner2022-10-29Added 5 answers

e raised to the power of a natural log cancels out both. This just leaves you with 2 x + 1 = 5 x , or x = 1 3

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