Prove that -(p_1+p_2) log(p_1+p_2) <= -p_1 log(p_1) - p_2 log(p_2) provided that p_1,p_2 > 0

Laila Murphy

Laila Murphy

Answered question

2022-11-04

Prove that ( p 1 + p 2 ) log p 1 + p 2 p 1 log p 1 p 2 log p 2 provided that p 1 , p 2 > 0
WTS:
( p 1 + p 2 ) log ( p 1 + p 2 ) p 1 log p 1 p 2 log p 2 p 1 , p 2 > 0
Any hints on this? I've tried to set it up as a proof by contradiction, and jiggled around with the terms both as logarithms and after exponentiating everything, but no luck.

Answer & Explanation

mignonechatte00f

mignonechatte00f

Beginner2022-11-05Added 13 answers

p 1 log ( p 1 ) + p 2 log ( p 2 ) p 1 log ( p 1 + p 2 ) p 2 log ( p 1 + p 2 ) = p 1 ( log ( p 1 ) log ( p 1 + p 2 ) ) + p 2 ( log ( p 2 ) log ( p 1 + p 2 ) ) 0 + 0 = 0

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