How to solve logarithm word problem given the exponential equation? The question is The world population in 2000 was approximately 6.08 billion. The annual rate of increase was about 1.26%. The function that models this is y = 6.08(10)^(.0052t) where y represents the population in billions and t is the time in years after 2000. Write and solve a logarithmic equation to determine what year the world population will exceed 7.5 billion. So is the question asking me to convert the given equation into logarithmic equation than 7.05 = 6.08(10)^(.0052t) ( 7.5 billion is y right?)

$\frac{20b}{{\left(4b^3\right)}^3}$

Which operation could we perform in order to find the number of milliseconds in a year??
${\displaystyle 60\cdot 60\cdot 24\cdot 7\cdot 365}$
${\displaystyle 1000\cdot 60\cdot 60\cdot 24\cdot 365}$
${\displaystyle 24\cdot 60\cdot 100\cdot 7\cdot 52}$
${\displaystyle 1000\cdot 60\cdot 24\cdot 7\cdot 52?}$

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A) No
B) 0
C) Yes
D) 6

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149600000000 is equal to
A)$1.496\times <!--\; \times \; -->{10}^{11}$
B)$1.496\times <!--\; \times \; -->{10}^{10}$
C)$1.496\times <!--\; \times \; -->{10}^{12}$
D)$1.496\times <!--\; \times \; -->{10}^8$

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write ${\displaystyle \sqrt[5]{{\left(7x\right)}^4}}$ as an equivalent expression using a fractional exponent.

simplify ${\displaystyle \sqrt{125n}}$

What is the square root of ${\displaystyle \frac{144}{169}}$