How can I find the roots of x^3-3x+1 using Cardano's formula?

Dayanara Nash

Dayanara Nash

Answered question

2022-11-27

How can I find the roots of x 3 3 x + 1 using Cardano's formula?
So far, I found that
x = 1 + 3 2 3 + 1 3 2 3
x = 1 + i 3 2 3 + 1 i 3 2 3
x = 1 2 + i 3 2 3 + 1 2 i 3 2 3
I am now trying to express each cubic radicand in their exponential form.

Answer & Explanation

kriteria0b1

kriteria0b1

Beginner2022-11-28Added 10 answers

Use the Cardano approach:
Let
x = u + v
then we will get
u 3 + v 3 + 3 ( u v 1 ) ( u + v ) + 1 = 0
by setting u v 1 = 0 we get
u v = 1
and
u 3 + v 3 = 1
by cubing the first equation we obtain a simple quadratic system in terms of u 3 and v 3 which you can be reduced to a quadratic equation in terms of u 3 for example:
u 3 + 1 u 3 + 1 = 0
Then use the Quadratic formula to find u 3 and v 3 = 1 u 3
After extracting cubic roots of the obtained solution you need to take into account that uv is real. This will give the appropriate pairs of u and v whose sums will yield all three roots of the equation.

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