A solution containing 5.24 mg/100 mL of A

Chaitanya Bhasakhetre

Chaitanya Bhasakhetre

Answered question

2022-09-18

A solution containing 5.24 mg/100 mL of A (335 g/mol) has a transmittance of 55.2% in a 1.50-cm cell at 425 nm.find molar absorbtivity

Answer & Explanation

nick1337

nick1337

Expert2023-05-28Added 777 answers

To find the molar absorptivity, we can use the Beer-Lambert Law, which relates the transmittance (T) of light through a solution to the concentration (c), path length (l), and molar absorptivity (ε) of the absorbing species.
The Beer-Lambert Law is given by:
T=exp(ε·c·l)
In the given problem, we have:
T=0.552 (transmittance)
c=5.24mg/100 mL=0.0524g/L (concentration)
l=1.50cm (path length)
We are asked to find ε (molar absorptivity).
Substituting the given values into the Beer-Lambert Law equation, we have:
0.552=exp(ε·0.0524·1.50)
To solve for ε, we need to isolate it. Taking the natural logarithm (ln) of both sides, we get:
ln(0.552)=ε·0.0524·1.50
Now, we can solve for ε by dividing both sides by 0.0524·1.50 and multiplying by 1:
ε=ln(0.552)0.0524·1.50
Using a calculator, we can evaluate this expression to find the value of ε.
The molar absorptivity is represented as:
ε=ln(0.552)0.0524·1.50

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