How to find instantaneous velocity from a position vs. time graph?

Lexi Holmes

Lexi Holmes

Answered question

2023-03-24

How to find instantaneous velocity from a position vs. time graph?

Answer & Explanation

obwiertzy5w

obwiertzy5w

Beginner2023-03-25Added 5 answers

The instantaneous velocity at any given point in a graph of position versus time p ( x , t ) on the function x ( t ) is the derivative of the function x ( t ) with respect to time at that point.
The derivative of a function at any given point is simply the instantaneous rate of change of the function at that point. In the case of a graph of position (or distance) vs. time, that means that the derivative at a given point p 0 ( t 0 , x 0 ) is the instantaneous rate of change in position (accounting for ""positive"" and ""negative"" direction) with respect to time.
As an example, consider a linear distance function (that is, one which can be represented with a line as opposed to a curve). If this were a function of x and y , with y as the dependent variable, then our function in slope-intercept form would take the form y = m x + b , where m is the slope and b is the value of y at x = 0 . In this case, t is our independent variable and x is our dependent, so our linear function would take the form x ( t ) = m t + b .
From algebra, we know that the slope of a line measures the number of units of change in the dependent variable for every single unit of change in the independent variable. Thus, in the line x ( t ) = 2 t + 5 , for every one unit by which t increases, x increases by 2 units. If we were to, for example, assign units of seconds to t and feet to x , then every second that passed (that is, every increase of one second in t ), position (or distance) would increase by two feet (that is x would increase by two feet)
Since our change in distance per unit of change in time will remain the same no matter our starting point ( x 0 , t 0 ) , in this case we can be assured that our instantaneous velocity is the same throughout. Specifically, it is equal to m = 2 . Differentiating the function with respect to t yields the same answer. Note that this is only identical to our average velocity throughout the function by design: for a non-linear function (such as x ( t ) = t 2 ) this would not be the case, and we would need to use differentiation techniques to find the derivatives of such functions.

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