How to find instantaneous velocity from a position vs. time graph?
Lexi Holmes
Answered question
2023-03-24
How to find instantaneous velocity from a position vs. time graph?
Answer & Explanation
obwiertzy5w
Beginner2023-03-25Added 5 answers
The instantaneous velocity at any given point in a graph of position versus time on the function is the derivative of the function with respect to time at that point. The derivative of a function at any given point is simply the instantaneous rate of change of the function at that point. In the case of a graph of position (or distance) vs. time, that means that the derivative at a given point is the instantaneous rate of change in position (accounting for ""positive"" and ""negative"" direction) with respect to time. As an example, consider a linear distance function (that is, one which can be represented with a line as opposed to a curve). If this were a function of and , with as the dependent variable, then our function in slope-intercept form would take the form , where is the slope and is the value of at . In this case, is our independent variable and is our dependent, so our linear function would take the form . From algebra, we know that the slope of a line measures the number of units of change in the dependent variable for every single unit of change in the independent variable. Thus, in the line , for every one unit by which increases, increases by 2 units. If we were to, for example, assign units of seconds to and feet to , then every second that passed (that is, every increase of one second in ), position (or distance) would increase by two feet (that is would increase by two feet) Since our change in distance per unit of change in time will remain the same no matter our starting point , in this case we can be assured that our instantaneous velocity is the same throughout. Specifically, it is equal to . Differentiating the function with respect to yields the same answer. Note that this is only identical to our average velocity throughout the function by design: for a non-linear function (such as ) this would not be the case, and we would need to use differentiation techniques to find the derivatives of such functions.