We are given: ²2x²+4x+1=0 The left side is not factorable so use the quadratic formula is given by: x=−b±(b2−4ac)2a Substitute a=2, b=4, and c=1; x=(−4+−((42)−4(2)(1)))/2(2)x=(−4+−8)/4x=(−4+−22)/4x=(−2+−2)/2

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Answered question

2021-05-11

2 x ² + 4 x + 1 = 0

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unessodopunsep

Skilled2021-05-12Added 105 answers

We are given: $2 x ² + 4 x + 1 = 0$
The left side is not factorable so use the quadratic formula is given by: $x = \frac{- b \pm (\sqrt{b^{2}} - 4 a c)}{2} a$ Substitute a=2, b=4, and c=1;

$x = (- 4 + - (\sqrt{(} 4^{2}) - 4 (2) (1))) / 2 (2) x = (- 4 + - \sqrt{8}) / 4 x = (- 4 + - 2 \sqrt{2}) / 4 x = (- 2 + - \sqrt{2}) / 2$

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