Begin by graphing f(x)= \log_{2}x and then use transformations of this graph to graph the given function: h(x)=-1+ \log_{2}x

tricotasu

tricotasu

Answered question

2021-08-05

Begin by graphing
f(x)=log2x.
Then use transformations of this graph to graph the given function. What is the graph's x-intercept? What is the vertical asymptote? Use the graphs to determine each functions domain and range.
h(x)=1+log2x

Answer & Explanation

Aniqa O'Neill

Aniqa O'Neill

Skilled2021-08-06Added 100 answers

Step 1
Graph of f(x)=log2x
image

Step 2
image Answer: Graph of h(x)=1+log2x. The graph is translated down 1 unit from the graph f(x).
The vertical asymptote is x=0. The x-intercept is (2,0. The domain of h(x) is {xx>0}. The range is all real numbers.

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