facas9

2020-11-22

Find the x-and y-intercepts of the graph of the equation algebraically.

$y=-\frac{1}{2}x+\frac{2}{3}$

broliY

Skilled2020-11-23Added 97 answers

Calculation:

Consider, the equation,

$y=-\frac{1}{2}x+\frac{2}{3}$

To determine x -intercept, substitute$y=0$ in the above equation,

$0=-\frac{1}{2}x+\frac{2}{3}$

$\frac{1}{2}x=\frac{2}{3}$

$x=\frac{2}{3}\times 2$

$=\frac{4}{3}$

Therefore, the x -intercept is$(\frac{4}{3},0)$ .

To determine y -intercept, substitute$x=0$ in the equation, $y=-\frac{1}{2}x+\frac{2}{3}$ ,

$y=-\frac{1}{2}\times 0+\frac{2}{3}$

$=\frac{2}{3}$

Therefore, y -intercept is$(0,\frac{2}{3})$ .

Consider, the equation,

To determine x -intercept, substitute

Therefore, the x -intercept is

To determine y -intercept, substitute

Therefore, y -intercept is

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A) I only

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x-6y-5=0

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What are the missing zeros?

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