Find a polyn. function of degree 3 with 4,i,-i as zeros. A)f(x)=x^3-4i *x^2+x-4i

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2022-04-12

Answer & Explanation

user_27qwe

user_27qwe

Skilled2023-04-27Added 375 answers

To find a polynomial function of degree 3 with 4, i-i as zeros, we first need to use the conjugate property of complex numbers to obtain a total of 4 distinct roots. The conjugate of i-i is i+i = 2i, so our 4 roots are 4, i-i, 2i, and -2i.
Since a polynomial function of degree 3 has 3 roots, we can use these 4 roots to form a cubic polynomial by using the fact that (x-r1)(x-r2)(x-r3) = 0, where r1, r2, and r3 are the roots of the polynomial.
Therefore, our polynomial function is given by:
f(x)=(x4)(xi+i)(x2i)(x+2i)
Expanding this expression and simplifying, we get:
f(x)=(x4)(x2+2ix2ix+4i2)(x24i2)
f(x)=(x4)(x2+4)(x2+4i2)
f(x)=(x4)(x2+4)(x24) (since i2=1)
f(x)=(x4)(x216)(x2+4)
f(x)=x54x412x3+64x2+64x256
Therefore, the polynomial function of degree 3 with 4, i-i as zeros is f(x)=x54x412x3+64x2+64x256.

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