Carol Gates

2021-05-19

Use the row of numbers shown below to generate 12 random numbers between 01 and 99.
78038 18022 84755 23146 12720 70910 49732 79606
Starting at the beginning of the row, what are the first 12 numbers between 01 and 99 in the sample?

comentezq

We must pair up two digits, beginning with the first digit of the row. The 12 random numbers produced by the given row are as follows: 78 , 03, 81, 80, 22, 84, 75, 52, 31, 46, 12, 72

xleb123

To generate 12 random numbers between 01 and 99 using the given row of numbers, we can follow these steps:
1. Separate the given row of numbers into individual digits:
$7$, $8$, $0$, $3$, $8$, $1$, $8$, $0$, $2$, $2$, $8$, $4$, $7$, $5$, $5$, $2$, $3$, $1$, $4$, $6$, $1$, $2$, $7$, $2$, $0$, $7$, $0$, $9$, $1$, $0$, $4$, $9$, $7$, $3$, $2$, $7$, $9$, $6$, $0$, $6$.
2. Combine the digits to form two-digit numbers, discarding any numbers outside the range of 01 to 99:
$78$, $03$, $80$, $22$, $84$, $75$, $52$, $31$, $46$, $12$, $70$, $91$.
3. Output the first 12 numbers:
$78$, $03$, $80$, $22$, $84$, $75$, $52$, $31$, $46$, $12$, $70$, $91$.
Therefore, the first 12 numbers between 01 and 99 in the given sample are:
$78$, $03$, $80$, $22$, $84$, $75$, $52$, $31$, $46$, $12$, $70$, $91$.

Jazz Frenia

Step 1: Normalize the given row of numbers to be between 0 and 1. We can do this by dividing each number by 99999 (the maximum possible value in the given row).
$\begin{array}{c}\hfill \frac{78038}{99999},\frac{18022}{99999},\frac{84755}{99999},\frac{23146}{99999},\frac{12720}{99999},\frac{70910}{99999},\frac{49732}{99999},\frac{79606}{99999}\end{array}$
Step 2: Multiply each normalized number by 98 (the difference between the desired range 01 to 99).
$\begin{array}{c}\hfill \frac{78038}{99999}×98,\frac{18022}{99999}×98,\frac{84755}{99999}×98,\frac{23146}{99999}×98,\frac{12720}{99999}×98,\frac{70910}{99999}×98,\frac{49732}{99999}×98,\frac{79606}{99999}×98\end{array}$
Step 3: Round each result to the nearest whole number.
$\begin{array}{c}\hfill \text{Round}\left(\frac{78038}{99999}×98\right),\text{Round}\left(\frac{18022}{99999}×98\right),\text{Round}\left(\frac{84755}{99999}×98\right),\text{Round}\left(\frac{23146}{99999}×98\right),\text{Round}\left(\frac{12720}{99999}×98\right),\\ \hfill \text{Round}\left(\frac{70910}{99999}×98\right),\text{Round}\left(\frac{49732}{99999}×98\right),\text{Round}\left(\frac{79606}{99999}×98\right)\end{array}$
Step 4: Add 1 to each rounded number to get the desired range between 01 and 99.
$\begin{array}{c}\hfill \text{Round}\left(\frac{78038}{99999}×98\right)+1,\text{Round}\left(\frac{18022}{99999}×98\right)+1,\text{Round}\left(\frac{84755}{99999}×98\right)+1,\\ \hfill \text{Round}\left(\frac{23146}{99999}×98\right)+1,\text{Round}\left(\frac{12720}{99999}×98\right)+1,\text{Round}\left(\frac{70910}{99999}×98\right)+1,\\ \hfill \text{Round}\left(\frac{49732}{99999}×98\right)+1,\text{Round}\left(\frac{79606}{99999}×98\right)+1\end{array}$
The first 12 numbers
between 01 and 99 in the sample, starting from the beginning of the row, are as follows:
$\begin{array}{cc}\hfill & \overline{)79},\overline{)18},\overline{)85},\overline{)23},\overline{)13},\overline{)72},\overline{)50},\overline{)80},\hfill \\ \hfill & 79,81,83,89\hfill \end{array}$

Andre BalkonE

$71,25,46,27,81,20,76,84,18,35,67,72$
Explanation:
To solve the problem and generate 12 random numbers between 01 and 99 using the given row of numbers, we can use a simple modulo operation.
$78038,18022,84755,23146,12720,70910,49732,79606$
To generate the random numbers, we will use the modulo operator mod. The modulo operator returns the remainder when a number is divided by another number. In this case, we will use it to restrict the range of the generated numbers to be between 01 and 99.
Let's generate the first random number. We start at the beginning of the row and take the first number, which is 78038. To restrict it to the range 01-99, we apply the modulo operator:
$78038\phantom{\rule{1em}{0ex}}\mathrm{mod}\phantom{\rule{0.333em}{0ex}}99=71$
The first random number is 71. Now, we move to the next number in the row, which is 18022, and apply the modulo operation:
$18022\phantom{\rule{1em}{0ex}}\mathrm{mod}\phantom{\rule{0.333em}{0ex}}99=25$
The second random number is 25. We continue this process for the remaining numbers in the row, generating a total of 12 random numbers between 01 and 99.
The generated random numbers are:
$71,25,46,27,81,20,76,84,18,35,67,72$

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