How many different 10 letter words (real or imaginary) can be formed from the following letters H,T,G,B,X,X,T,L,N,J

Khadija Wells

Khadija Wells

Answered question

2021-06-01

How many different 10 letter words (real or imaginary) can be formed from the following letters
H,T,G,B,X,X,T,L,N,J

Answer & Explanation

timbalemX

timbalemX

Skilled2021-06-02Added 108 answers

Solution to your problem:

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Jeffrey Jordon

Jeffrey Jordon

Expert2021-09-28Added 2605 answers

So we have, the following letters.

H,T,G,B,X,X,T,L,N,J

From the letters above, a variety of 10 letter words can be created.

Number of letters in the word = 10

The number of repetitions of the letters in the respective word =2!2!

Remember the equation,

The total number of words in a given letters =n!a!b!

Here n= Number of letters in the word "n"=10

a=2! (Letter T repeating 2 times)

b=2! (Letter X repeating 2 times)

Therefore, total number of words =102!2!

=10987654321(21)(21)=907200

Then, the total number of word is 907 200 

karton

karton

Expert2023-06-18Added 613 answers

The total number of different 10-letter words is given by the formula:
10!2!·2! where 10! represents the factorial of 10 (10 factorial), and 2! accounts for the repeated permutations of the letter X and the repeated permutations of the letter T.
By simplifying the expression, we get:
10·9·8·7·6·5·4·3·2·12·1·2·1=90,720
Therefore, there are 90,720 different 10-letter words that can be formed from the given letters.
alenahelenash

alenahelenash

Expert2023-06-18Added 556 answers

The number of different 10-letter words that can be formed from the given letters ''H, T, G, B, X, X, T, L, N, J'' can be calculated using the concept of permutations.
We have a total of 10 letters, but there are two repeated letters (X and T). So, we need to take into account these repetitions while calculating the permutations.
To find the number of permutations, we can use the formula:
n!n1!·n2!·n3!·...
Where:
- n is the total number of items (10 in this case).
- n1,n2,n3, etc., represent the number of repetitions of each item.
In this case, we have:
- n=10 (total letters)
- n1=2 (number of X's)
- n2=2 (number of T's)
Substituting the values into the formula, we get:
10!2!·2!
user_27qwe

user_27qwe

Skilled2023-06-18Added 375 answers

Answer: 3,628,800
Explanation:
The total number of letters we have is 10. Let's denote this as n.
We can use the formula for permutations of n objects taken r at a time:
P(n,r)=n!(nr)!
In our case, n is 10 (the total number of letters), and r is also 10 (since we want to form 10-letter words).
Substituting these values into the formula, we get:
P(10,10)=10!(1010)!
Simplifying further:
P(10,10)=10!0!
Since 0! is equal to 1, we can simplify again:
P(10,10)=10!1
Now we can calculate the value of 10!:
10!=10×9×8×7×6×5×4×3×2×1
10!=3,628,800
Therefore, the total number of different 10-letter words that can be formed using the given letters is 3,628,800.

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