The given polynomial x2−22x+72 and factors by multiplying.

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svartmaleJ · Accepted Answer

Calculation: We have a quadrratic x2−22x+72.  In order to factor the given quadratic we need to compare given quadratic with standard quadratic ax2+bx+c.  Now, we need to get the values of a, b and c and product sum rule to factor the quadratic.  On comparing given quadratic x2−22x+72 with standard quadratic   ax2+bx+c,  we get a=1,b=−22,c=72.  Product of value of a and c=1×72=72.  Value of b=−22.  Now, we need to get two factors of 72 those add upto -22.  We could see 72=−18×(−4),−22=−4+(−18)  So, split middle term −22xinto−4x−18x, we get  x2−4x−18x+72  Now, making it into two groups and factor out Greatest  Common Factor (GCF) of each group (x2−4x)+(−18x+72)  Factor out Greates Common Factor (GCF)xfrom(x2−4x)  and -18 from (−18x+72)  x(x−4)−18(x−4)  Factor out the common parenthesis (x−4)  (x−4)(x−18)  Now, let us check its

The given polynomial x^{2} - 22x + 72 and factors by multiplying.

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