kuCAu
2020-12-14
Nichole Watt
Skilled2020-12-15Added 100 answers
The equation for C is
on the x-axis with a
The point on the circle C is(x, y).
Obtain the distance between (x, y) and (a, 0) as follows:
Now, obtain the partial derivatives as follows,
Thus, the critical point is(a, 0). However, this point doesn’t lie on the circle C.
We know the endpoints on the circles are (-r, 0) and (r, 0).
Thus, the distance becomes
At (-r, 0),
and at (r, 0),
Apart from these two points, no other point gives these distances but between
Also, these two points lie on the line from (a, 0) that passes through the center of C.
Thus, the maximum distance from the point P (a, 0) to the point
and the minimum distance from the point P (a, 0) to the point
Hence, the maximum and minimum distances from P toa point X on C occur when the line XP goes through the center of C.
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B)
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D)
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