I have a question:
With the given sample, you want to calculate the population mean .
You think the population is dispersed normally. Find the 99.99 percent confidence level range. Put your response in parenthesis as an open-interval that is accurate to two decimal places (because the sample data are reported accurate to one decimal place).
Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Excel is used to compute the sample mean and sample standard deviation.
And standard deviation-
Sample standard deviation,
So, significance level,
We shall employ the t-distribution because the population's standard deviation is unknown here.
Now, degree of freedom is given by-
Degree of freedom,
Degree of freedom,
Now, confidence interval is given by
So, t-critical is given by
So, confidence interval is 33.81 to 63.42
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78038 18022 84755 23146 12720 70910 49732 79606
Starting at the beginning of the row, what are the first 12 numbers between 01 and 99 in the sample?
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2) 3.5 Hours
3) 6 Hours
4) 12.5 Hours
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