Dottie Parra

2021-01-10

A group of 125 truck owners were asked what brand of truck they owned and whether or not the truck has four-wheel drive. The results are summarized in the two-way table below. Suppose we randomly select one of these truck owners.

$\begin{array}{ccc}& \text{Four-wheel drive}& \text{No four-wheel drive}\\ \text{Ford}& 28& 17\\ \text{Chevy}& 32& 18\\ \text{Dodge}& 20& 10\end{array}$

What is the probability that the person owns a Dodge or has four-wheel drive?

$(a)\frac{20}{80}$

$(b)\frac{20}{125}$

$(c)\frac{80}{125}$

$(d)\frac{90}{125}$

$(e)\frac{110}{125}$

What is the probability that the person owns a Dodge or has four-wheel drive?

Nathalie Redfern

Skilled2021-01-11Added 99 answers

Given:

Let us first determine the row/column totals, which is the sum of all counts in the row/column.

The table contains 125 people in total, which is given in the bottom right corner of the table.

The people who own a dodge or have four-wheel drive are given in the row "Dodge” and given in the column ”Four-wheel drive” of the above table, which corresponds with 28+ 32+ 20+ 10= 90 people.

Thus 90 of the 125 people own a dodge or have four-wheel drive.

The probability is the number of favorable outcomes divided by the number of possible outcomes:

Answer: (d)

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