Let X be a normal random variable with mean 12 and variance 4. Find the value of

chanyingsauu7

chanyingsauu7

Answered question

2021-11-07

Let X be a normal random variable with mean 12 and variance 4. Find the value of c such that P[X>c]=.10.

Answer & Explanation

Drood1980

Drood1980

Beginner2021-11-08Added 16 answers

Given: X is a normal random variable with mean μ=12 and variance σ2=4 
To determine: A value for c that P[X>c]=0.10 
Explanation: We have 
P[X>c]=0.1 
P[Xc]=10.1=0.9 
P[Xμσc122]=0.9 
P[Zc122]=0.9 
Φ(c122)=0.9 
c122=1.28 
c12=2.56 
c=14.56 
Therefore: 
Value of c = 14.56

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