What are the mean and standard deviation of a binomial probability distribution with n=12 and p=760?

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David Clayton · Accepted Answer

Explanation:  The mean and standard deviation of a binomial probability distribution are np and npq respectively where n is number of trials and p is probability of success of the event. Here q=1-p, and is the probability of failure of the event.  With n =12 and p=760,q=1−760=5360.  Hence mean is 12×760=75=1.4 and  Standard Deviation is 12×760×5360=(160)7×12×53  =445260=66.723360=1.112

Anzante2m · Accepted Answer

Solution:  The mean of the binomial distribution is interpreted as the mean number of successes for the distribution. To find the mean, use the formula  μ=n⋅p  where n is the number of trials and p is the probability of success on a single trial. Substituting values for this problem, we have  μ=12⋅760  Multiplying the expression we have  μ=1.392  The standard deviation of the binomial distribution is interpreted as the standard deviation of the number of successes for the distribution. To find the standard deviation, use the formula  σ=n⋅p⋅(1−p)  where n is the umber of trials and p is the probability of success on a single trial. Substituting values fo this problem, we have  σ=12⋅760⋅(1−760)  Evaluating the expression on the right, we have  σ=1.23  σ=1.112

What are the mean and standard deviation of a binomial

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