A population of values has a normal distribution with \mu = 200 and \sigma = 31.9. You intend to draw a random sample of size n = 11

Isa Trevino

Isa Trevino

Answered question

2020-10-28

A population of values has a normal distribution with μ=200 and σ=31.9. You intend to draw a random sample of size n=11.
Find the probability that a single randomly selected value is less than 226.9.
P(X<226.9)=?
Write your answers as numbers accurate to 4 decimal places.

Answer & Explanation

izboknil3

izboknil3

Skilled2020-10-29Added 99 answers

The probability that a single randomly selected value is less than 226.9 is,
PX<226.9=PX-μσ<226.9-20031.9
=Pz<26.931.9
=Pz<0.843
The probability of z less than 0.843 can be obtained using the excel formula “=NORM.S.DIST(0.843,TRUE)”. The probability value is 0.8004.
The required probability value is,
PX<226.9=Pz<0.843=0.8004
Thus, the probability that a single randomly selected value is less than 226.9 is 0.8004.

Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-14Added 2605 answers

Answer is given below (on video)

Do you have a similar question?

Recalculate according to your conditions!

New Questions in College Statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?