A distribution of values is normal with a mean of 79.5 and a standard deviation of 7.4.Find the probability that a randomly selected value is between 71.4 and 78.P(71.4 < x < 78) = P( < z < ) =?

allhvasstH

allhvasstH

Answered question

2021-01-19

A distribution of values is normal with a mean of 79.5 and a standard deviation of 7.4.
Find the probability that a randomly selected value is between 71.4 and 78.
P(71.4<x<78)=P(<z<)=?

Answer & Explanation

bahaistag

bahaistag

Skilled2021-01-20Added 100 answers

Step 1:
A distribution of values is normal
Mean = 79.5
Standard deviation = 7.4
Step 2: Probability is given by,
The probability that a randomly selected value is between 71.4 and 78 is given by,
P(71.4<X<78)=P(71.479.57.4<xμσ<7879.57.4)
P(71.4<X<78)=P(1.09<Z<0.20)
P(71.4<X<78)=0.2828
By using Standard normal table.

Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-17Added 2605 answers

Answer is given below (on video)

Do you have a similar question?

Recalculate according to your conditions!

New Questions in College Statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?