A recent study sought to determine if exercising after studying for an exam may help retain information. The 150 student volunteers that participated in the study were randomly assigned to three groups. All students were given a picture memory task that they studied for 15 minutes. After studying, one of the groups was instructed to exercise for 30 minutes immediately after studying. A second group was instructed to wait 1 hour after studying and then exercise for 30 minutes. The third group was instructed to not exercise after studying. The next day all 150 student volunteers were given a test to determine how well they could remember what they studied. Here are the results:The researchers want to test: H0: There is no difference in the distribution of performance on the test for the three treatment groups among the population of all student volunteers like these.Hα: There is a difference in the distribution of performance on the test for the three treatment groups among the population of all student volunteers like these.Which test is appropriate in this situation?(A) chi-square test for homogeneity(B) chi-square test for association(C) chi-square test for goodness of fit(D) two-sample test for p_1-p_2p1-p2(E) matched pairs tt testTreatment GroupPerformance on the Test Exercise immediately Exercise 1 hour later Do not exercise Total Less than 50% 682539 50% to 75% 22282272 Greater than 75% 2214339 Total 505050150

Question

A recent study sought to determine if exercising after studying for an exam may help retain information. The 150 student volunteers that participated in the study were randomly assigned to three groups. All students were given a picture memory task that they studied for 15 minutes. After studying, one of the groups was instructed to exercise for 30 minutes immediately after studying. A second group was instructed to wait 1 hour after studying and then exercise for 30 minutes. The third group was instructed to not exercise after studying. The next day all 150 student volunteers were given a test to determine how well they could remember what they studied. Here are the results:The researchers want to test: H0: There is no difference in the distribution of performance on the test for the three treatment groups among the population of all student volunteers like these.Hα: There is a difference in the distribution of performance on the test for the three treatment groups among the population of all student volunteers like these.Which test is appropriate in this situation?(A) chi-square test for homogeneity(B) chi-square test for association(C) chi-square test for goodness of fit(D) two-sample test for p_1-p_2p1​-p2​(E) matched pairs tt testTreatment GroupPerformance on the Test Exercise immediately  Exercise 1 hour later  Do not exercise  Total  Less than 50% 682539 50% to 75% 22282272 Greater than 75% 2214339 Total 505050150

Arlene Patel · Accepted Answer

Given that:Treatment GroupPerformance on the Test Exercise immediately  Exercise 1 hour later  Do not exercise  Total  Less than 50% 682539 50% to 75% 22282272 Greater than 75% 2214339 Total 505050150 Hypothesis:The researchers want to test: H0: There is no difference in the distribution of performance on the test for the three treatment groups among the population of all student volunteers like these.Hα: There is a difference in the distribution of performance on the test for the three treatment groups among the population of all student volunteers like these.For this situation we have to use Chi-square test for association.Chi-square test of association:This test tests the association between two or more categorical variables.Assumptions:1. Two categorical variables2. Two or more groups3. Observations are independent.4. large sample size

Manraj Horton · Accepted Answer

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A recent study sought to determine if exercising after studying for an exam may help retain informat

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