You are conducting a test of homogeneity for the claim that two different populations have the same

fellesturduj

fellesturduj

Answered question

2022-03-09

You are conducting a test of homogeneity for the claim that two different populations have the same proportions of the following two characteristics. Here is the sample data.
 Category  Population #1  Population #2  A 1114 B 56105
What is the chi-square test-statistic for this data?
χ2=
Report all answers accurate to three decimal places.

Answer & Explanation

RI5N6mv3

RI5N6mv3

Beginner2022-03-10Added 3 answers

We have been given the observed frequencies (Oi) as,
 Category  Population #1  Population #2  Total  A 111425 B 56105161 Total 67119186
We compute the expected frequency as,
Expected frequency =(Column total×Row total)Grand total
The expected frequencies (Ei) are given by,
 Category  Population #1  Population #2  Total  A 67×25186=9.005376119×25186=15.9946225 B 67×161186=57.99462119×161186=103.0054161 Total 67119186
The chi-square test statistic is computed as,
χ2=i(OiEi)2Ei
=(119.005376)29.005376+(5657.99462)257.99462+(1415.99462)215.99462+(105103.0054)2103.0054=0.798
Thus, the chi-square test statistic is 0.798.

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