Jeffrey Ali
2022-03-18
Theresa Bullock
Beginner2022-03-19Added 2 answers
Given that, sample size n= 155
And X= 45
Population proportion is given by,
P= X/n
= 45/155
P= 0.290
(b)
We know that Q= 1-P
Q= 1-0.290
Q= 0.710
Standard error for proportion is given by,
SE. =
=
SE= 0.036
(c) To test significance of proportion, we use z test (Normal Distribution) at the given level of significance.
(d) Test Statistic for proportion is,
for test of significance for proportion
=
statistic
same proportion
P population proportion
Q Q=(1-P)
n number of elements in large sample
Given, sample proportion p= 0.25
Z= (0.25-0.290)/0.036
= 0.04/0.036
= 1.11
Testing at significance level alpha= 0.05 , the rejection region 1.645 is greater than 1.11
So we fail to reject null hypothesis.
We conclude that There is no evidence to suggest that the true proportion of the population of all NUIG students who regularly cooked their own food during term time, p, is greater than 0.25.
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