An approximate \(\displaystyle{95}\%\) confidence interval for the

Pelizzolaf40

Pelizzolaf40

Answered question

2022-03-15

An approximate 95% confidence interval for the true unemployment rate p is
(p^z2.5p^(1p^)n,p^z97.5p^(1p^)n)
=(0.0791.960.079(10.079)4148,0.079+1.960.079(10.079)4148)
=(0.071,0.087)
What I'm mainly confused about is: how did they jump immediately to their first line?

Answer & Explanation

RI5N6mv3

RI5N6mv3

Beginner2022-03-16Added 4 answers

Step 1
It's a standard result that an approximate 100(1α)% CI for a proportion p, obtained by observing x successes in a sequence of n independent Bernoulli trials each with success probability p is
(p^zp^(1p^)n,p^+zp^(1p^)n)
where p^=xn is the estimate of p and z is the (1α2) quantile of the standard normal distribution.
So yes, assumptions have been made about independent Bernoulli trials.

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