Are people born in certain seasons more likely

fellesturduj

fellesturduj

Answered question

2022-03-15

Are people born in certain seasons more likely to be allergic to dust mites? Research suggests this might be true. The table below gives the birth seasons of 500 randomly selected people who are allergic to dust mites, along with the expected proportion of people born in each season. Do these data provide convincing evidence that people who suffer from this allergy have a different birth season distribution?
 Birth Season  Numbers of allergy sufferers  Proportion of biths in general population  Winter 1170.30 Spring 1050.22 Summer 1450.24 Fall 1330.24

Answer & Explanation

diesel817637dsf

diesel817637dsf

Beginner2022-03-16Added 13 answers

Hypothesis testing is conducted for the parameters of the population like population mean, population standard deviation and so on. It is to check whether he sample values conforms to the pre stated parameter values of the original distribution or not. There are various test that are used while conducting the hypothesis testing. These are:
1.z test
2.t test
3. F test
4. Chi-square test.
The chi square test could be classified as:
1. Chi-square test for independence .
2. Chi-square test for goodness of fit
3. Chi-square test for homogeneity
The Chi-Square Test of Independence is mainly used to check whether there is an association between categorical or qualitative variables that is whether the variables are independent or related (dependent) or not.
The formula to compute the test statistic for chi-square test of independence is:
χ2=(OEE)2
Here,
χ2= Chi square test statistic
O=Observed frequency
E=Expected frequency
= Summation
The hypothesis:
H0: There is no difference in the proportions of people born in different season
Hα:There is a difference in the proportions of people born in different season
The calculation for the test statistic is done as:
OE(O-E)(O-E)2E117150-337.260105110-50.227145120255.208133120131.408
The test statistic is:
χ2=7.260+0.227+5.208+1.408=14.10
The test statistic is 14.10.
The degree of freedom is:
df=Number of categories-1=4-1=3
The p-value is 0.003.
Here, p-value < assumed significance level (0.05). The null hypothesis is rejected.
Hence, we can conclude that there is a difference in the distribution of proportion.

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