Suppose a researcher used a sample of 400
Aleah Choi
Answered question
2022-04-03
A. There is a significant preference at both the .05 level of significance and the .01 level of significance
B. There is no significant preference at any level of significance
C. There is a significant preference at the .05 level of significance but not at the .01 level of significance
D. There is a significant preference at the .01 level of significance but not
at the .05 level of significance
11. What is indicated by an extremely large calculated value of Chi-square in a one-way Chi-square test?
A. There is a perfect match between the observed frequencies in the sample and the null hypothesis
B. The observed frequencies in the sample are very different from the expected frequency
C. The observed frequencies in the sample are very similar to the expected frequency
D. None of the above
12. Suppose a researcher is using a two-way Chi-square test to evaluate the relationship between birth-order position and self-esteem. Each participant is classified as being 1st born, 2nd born, or 3rd born, and self-esteem is categorized as being low, medium, or high. In this study, the number of degree(s) of freedom (df) would be:
A. 1
B. 4
C. 3
D. 2
Answer & Explanation
diocedss33
Beginner2022-04-04Added 12 answers
The value of the chi-square test statistic is 9.07
degrees of freedom = (c-1)
where c is the number of categories
we have c = 3
degrees of freedom = (3-1)=2
p-value = P
10. The value of the chi-square test statistic is 9.07
degrees of freedom = (c-1)
where c is the number of categories
we have c = 3
degrees of freedom = (3-1)=2
p-value
decision : the p-value is less that the significance level of 0.05 but greater than significance level of 0.01, therefore we can conclude as follows-There is a significant preferences at the .05 level of significance but not at the .01 level of significance.Hence option C is correct.
11. If the chi-square test statistic in the one-way chi-square test is high the P-value will be close to 0 that means we have more chances to rejecting the null hypothesis. in one way hypothesis the null hypothesis states that observed frequency is similar to expected which will by rejected so the answer will be.
b. The observed frequencies in the sample are very different from the expected frequency.
12. As the given above there will be two rows and three column in the table so to calculate d.f we will use following formula
D.f = number of rows -1 * number of columns -1
= 2-1 * 3-1
=2
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