There are 209 dogs who participate in a training to become service dogs.There are four breeds of dogs.Some dogs pass the certification test and some do not?Chi square question:Is there an association between breed of dog and passing the test? Or, are breed and passing the test independent of each other?Blank tables are provided for your calculations.1. What are the null and alternative hypotheses for the chi square test of independence?2. Calculate the expected frequencies for each “cell”3. Using the steps shown in the lecture and in the text, calculate the chi square to investigate whether “passed certification” and “breed of dog” are independent of each other or not.4. Compare your calculated chi square to the critical value of chi square per the table, using the correct degrees of freedom. Chihuahua French Bulldog Golden Retriever Terriers Total Trained and certified as therapy dog 20125037119 Trained but not certified as therapy dog 1515372390 Total who took the training 35278760209

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There are 209 dogs who participate in a training to become service dogs.There are four breeds of dogs.Some dogs pass the certification test and some do not?Chi square question:Is there an association between breed of dog and passing the test? Or, are breed and passing the test independent of each other?Blank tables are provided for your calculations.1. What are the null and alternative hypotheses for the chi square test of independence?2. Calculate the expected frequencies for each “cell”3. Using the steps shown in the lecture and in the text, calculate the chi square to investigate whether “passed certification” and “breed of dog” are independent of each other or not.4. Compare your calculated chi square to the critical value of chi square per the table, using the correct degrees of freedom. Chihuahua  French Bulldog  Golden Retriever  Terriers  Total  Trained and certified as therapy dog 20125037119 Trained but not certified as therapy dog 1515372390 Total who took the training 35278760209

phoenixtreeaung · Accepted Answer

It is given that there are 209 dogs with four breeds of bogs.Hypotheses:H0: There is no association between breed of dog and passing the test.H1: There is an association between breed of dog and passing the test.Observed Frequencies: Breeds  Pass the test  Chihuahua  French Bulldog  Golden Retriever  Terriers  Total  Trained and certified 20125037119 Trained but not certified 1515372390 Total 35278760209 Calculate the Expected Frequencies are as follows: Breeds  Pass the test  Chihuahua  French Bulldog  Golden Retriever  Terriers  Total  Trained and certified 35×119209=19.92827×119209=15.37387×119209=49.53660×119209=34.163119 Trained but not certified 35×90209=15.07227×90209=11.62787×90209=37.46460×90209=25.83790 Total 35278760209 Chi-square test statistic:χ2=∑{i=1}n(Oi−Ei)2EiCalculate the chi-square test statistic value is as follows:χ2=0.00026+0.74007+0.00435+0.23559+0.0034+0.97851+0.00575+0.31151=2.27638Therefore, the chi-square test statistic is 2.2764.Degrees of freedom:(r-1)(c-1)=(4-1)(2-1)=3Critical value:Calculate the critical value using Excel is as follows:Therefore, the critical value is 7.8147.Decision rule:If test statistic &amp;gt; critical value, then reject the null hypothesis.Here test statistic (2.27638) &amp;lt; critical value (7.8147), then fail to reject the null hypothesis.Conclusion:Therefore, there is no evidence to conclude that there is an association between breed of dog and passing the test.

There are 209 dogs who participate in a

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