A statistics practitioner took a random sample of 43 observations from a population whose standard deviation is 26 and computed the sample mean to be

SchachtN

SchachtN

Answered question

2021-01-10

A statistics practitioner took a random sample of 43 observations from a population whose standard deviation is 26 and computed the sample mean to be 108. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 95% confidence, changing the population standard deviation to 58, Confidence Interval = C. Estimate the population mean with 95% confidence, changing the population standard deviation to 8, Confidence Interval =

Answer & Explanation

toroztatG

toroztatG

Skilled2021-01-11Added 98 answers

Step 1

Given that, the sample mean is equal to 108. Statistical population deviation, σ=26. 43 people make up the sample; n. The 95% confidence interval's z-critical value is 1.96. The 95% confidence interval can be calculated as follows: CI=x±z(σn)
=108±1.96(2643)
=108±7.7713
=(100.2287,115.7713) The 95% confidence interval is (100.2287, 115.7713).

Step 2

b. Population standard deviation, σ is 58. You may compute the 95% confidence interval by using the formula below: CI=x±z(σn)
=108±1.96(5843)
=108±17.3360
=(90.664,125.336) The 95% confidence interval is (90.664,125.336).

Step 3

c. Population standard deviation, σ=8. Following are the steps to compute the 95% confidence interval: CI=x±z(σn)
=108±1.96(843)
=108±2.3911
=(105.6089,110.3911) The 95% confidence interval is (105.6089,110.3911).

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