In each of Exercises, we have provided a sample mean,

surgerh7a

surgerh7a

Answered question

2022-04-24

In each of Exercises, we have provided a sample mean, sample size, and population standard deviation. In each case, use the one-mean z-test to perform the required hypothesis test at the 5% significance level.
x = 24, n = 15, σ = 4, H0: μ = 22, Ha: μ > 22

Answer & Explanation

Tatairfzk

Tatairfzk

Beginner2022-04-25Added 12 answers

The test hypotheses are given below:
Null hypothesis:H0: μ = 22,
Alternative hypothesis: Ha: μ > 22.
Critical value approach:
Critical value:
For 5% level of significance,
α=10.95
α=0.05
Hence, the cumulative area to the left is,
Area to theleft = 1- Area to theright
=1-0.05
= 0.95
From Table of the standard normal distribution, the critical value is 1.645.
Test statistic:
z=xμσn
=2422415=1.94
Conclusion:
Here, the test statistic is less than the critical value.
For right-tailed test, the null hypothesis is not rejected.
Thus, it can be said that there is no sufficient evidence to reject the null hypothesis.

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