According to the article “Modeling and Predicting the Effects of Submerged Arc Weldment Process Parameters on Weldment

DofotheroU

DofotheroU

Answered question

2020-11-24

According to the article “Modeling and Predicting the Effects of Submerged Arc Weldment Process Parameters on Weldment Characteristics and Shape Profiles” (J. of Engr. Manuf., 2012: 1230–1240), the submerged arc welding (SAW) process is commonly used for joining thick plates and pipes. The heat affected zone (HAZ), a band created within the base metal during welding, was of particular interest to the investigators. Here are observations on depth (mm) of the HAZ both when the current setting was high and when it was lower. Non-high1.041.151.231.691.921.982.362.492.721.371.431.571.711.942.062.552.642.82High1.552.022.022.052.352.572.932.942.97                             c. Does it appear that true average HAZ depth is larger for the higher current condition than for the lower condition? Carry out a test of appropriate hypotheses using a significance level of .01.

 

Answer & Explanation

Faiza Fuller

Faiza Fuller

Skilled2020-11-25Added 108 answers

Step 1

Given: n1=18
n2=9
α=0.01 The mean is the sum of all values divided by the number of values: x1=1.04+1.15+1.23++2.55+2.64+2.82181.9261
x2=1.55+2.02+2.02++2.93+2.94+2.9792.3778 The variance is the sum of squared deviations from the mean divided by n1. The standard deviation is the square root of the variance: s1=(1.041.9261)2+.+(2.821.9261)21810.5694
s2=(1.552.3778)2+.+(2.972.3778)2910.5072

Given claim: larger the higher current condition. The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis and the alternative hypothesis state the opposite of each other. The null hypothesis needs to contain the value mentioned in the claim. H0:μ1=u2
Hα:μ1<μ2

Step 2

Determine the test statistic: t=x1x2s12n1+s22n2=1.92612.37780.5694218+0.5072292.093

Determine the degrees of freedom (rounded down to the nearest integer): =(s12n1+s22n2)(s12n1)2n11+(s22n2)2n21=(0.5694218+0.507229)2(0.5694218)2181+(

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