There are 3 lottery tickets one can choose from: <mtable columnalign="right right" rowspacing="

sembuang711q6

sembuang711q6

Answered question

2022-05-09

There are 3 lottery tickets one can choose from:
A l t e r n a t i v e s C h a n c e s O u t c o m e A 1 / 1000 $ 1000 999 / 1000 $ 0 B 1 / 100 $ 100 99 / 100 $ 0 C 1 / 2000 $ 1000 1 / 200 $ 100 1989 / 2000 $ 0
And the formula for computing the probabilities of final outcomes when a coin is flipped between lotteries A   &   B yields
P $ 1000 = 1 2 2 2000 = 1 2000
P $ 100 = 1 2 20 1000 = 10 1000
P 00 = 1 P $ 1000 P $ 100
= 1989 2000
So there are 3 different probabilities here. The first one, P $ 1000 is the probability of the outcome being 1000 dollars, which is (the probability of getting lottery A from the coin flip) x (the probability of the outcome being 1000 dollars). That makes sense from the table above. But the second one, P $ 100 , the probability of the outcome being 100 dollars should be 20 2000 or 1 100 . Why then is it 20 1000 ???

Answer & Explanation

rynosluv101swv2s

rynosluv101swv2s

Beginner2022-05-10Added 19 answers

You have some typos, and this might be clearer
P $ 1000 = 1 2 1 1000 = 1 2000
P $ 100 = 1 2 1 100 = 1 200 = 10 2000
P 00 = 1 P $ 1000 P $ 100 = 2000 2000 1 2000 10 2000 = 1989 2000

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