Semaj Christian

2022-06-26

The mean of eight numbers is 41. The mean of two of the numbers is 29. What is the mean of the other six numbers?

Jerome Page

Beginner2022-06-27Added 16 answers

There are 3 different sets of numbers involved here.

A set of six, a set of two and the set of all eight.

Each set has its own mean.

$mean=\frac{Total}{number\text{}of\text{}numbers}PRM=\frac{T}{N}$

Note that if you know the mean and how many numbers there are, you can find the total.

$T=M\times N$

You can add numbers, you can add totals, but you may not add means together.

So, for all eight numbers: The total is $8\times 41=328$

For two of the numbers: The total is $2\times 29=58$

Therefore the total of the other six numbers is 328-58=270

The mean of the six numbers $=\frac{270}{6}=45$

A set of six, a set of two and the set of all eight.

Each set has its own mean.

$mean=\frac{Total}{number\text{}of\text{}numbers}PRM=\frac{T}{N}$

Note that if you know the mean and how many numbers there are, you can find the total.

$T=M\times N$

You can add numbers, you can add totals, but you may not add means together.

So, for all eight numbers: The total is $8\times 41=328$

For two of the numbers: The total is $2\times 29=58$

Therefore the total of the other six numbers is 328-58=270

The mean of the six numbers $=\frac{270}{6}=45$

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