Milliousd

Milliousd

Answered question

2022-07-22

Answer & Explanation

Andre BalkonE

Andre BalkonE

Skilled2023-05-29Added 110 answers

To calculate the probability of the first 3 consecutive vehicles leaving the Boksburg warehouse on time for their deliveries tomorrow, we can use the concept of independent events.
Given that each vehicle leaving the warehouse has a 90% probability of leaving on time, we can calculate the probability of all three vehicles leaving on time by multiplying their individual probabilities together.
Let's denote the event leaving on time as A. We want to find the probability of three consecutive events A occurring.
Using the multiplication rule for independent events, the probability of three independent events A occurring is given by:
P(AAA)=P(A)×P(A)×P(A)
Since each vehicle has a 90% probability of leaving on time, the probability of each individual event A is 0.90.
Plugging in the values, we have:
P(AAA)=0.90×0.90×0.90
Simplifying the calculation:
P(AAA)=0.903=0.729
Therefore, the probability of the first 3 consecutive vehicles leaving the Boksburg warehouse on time for their deliveries tomorrow is 0.729 or 72.9% when expressed as a percentage.

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