Jesse Urbina
2022-07-31
The quality-control inspector of a production plant will reject a batch of syringes if two or more defective syringes are found in a random sample of twelve syringes taken from the batch. Suppose the batch contains 1% defective syringes.
(b)
Find 𝜇 (in terms of the number of syringes). (Enter a number. Enter your answer to two decimal places.)
𝜇 = syringes
What is the expected number of defective syringes the inspector will find? (Enter a number. Enter your answer to two decimal places.)
(c)
What is the probability that the batch will be accepted? (Enter a number. Round your answer to three decimal places.)
(d)
Find 𝜎 (in terms of the number of syringes). (Enter a number. Round your answer to three decimal places.)
𝜎 = syringes
Jazz Frenia
Skilled2023-05-29Added 106 answers
Given that the batch contains 1% defective syringes and the inspector will reject a batch if two or more defective syringes are found in a random sample of twelve syringes, we can find the mean (μ) and expected number of defective syringes.
To find the mean (μ), we multiply the probability of a defective syringe (p) by the total number of syringes (n):
μ = p * n
Here, p = 1% = 0.01 (probability of a defective syringe)
n = 12 (total number of syringes)
Substituting the values, we have:
μ = 0.01 * 12 = 0.12 syringes
Therefore, the mean (μ) is 0.12 syringes.
To find the expected number of defective syringes, we use the same formula:
Expected number of defective syringes = p * n
Substituting the values, we have:
Expected number of defective syringes = 0.01 * 12 = 0.12
Therefore, the expected number of defective syringes the inspector will find is 0.12.
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