Given there's a number generator which creates irregular numbers to 9. Given after 50 number eras as it were 5 of the created numbers are underneath 3 (i.e. 0,1 or 2) and the importance level is α = 1%. How can I test in the event that for this importance level the number generator is producing all numbers with equal probability? It is obvious to me that in the event that the number generator would be without a doubt producing the numbers with uniform likelihood, one would anticipate 15 created numbers between and 2 - but how do I test the nullhypothesis in this case accurately?

Lilah Hurst

Lilah Hurst

Answered question

2022-10-21

Given there's a number generator which creates irregular numbers to 9. Given after 50 number eras as it were 5 of the created numbers are underneath 3 (i.e. 0,1 or 2) and the importance level is α = 1%. How can I test in the event that for this importance level the number generator is producing all numbers with equal probability? It is obvious to me that in the event that the number generator would be without a doubt producing the numbers with uniform likelihood, one would anticipate 15 created numbers between and 2 - but how do I test the nullhypothesis in this case accurately?

Answer & Explanation

imperiablogyy

imperiablogyy

Beginner2022-10-22Added 13 answers

The distribution of the number of results 0, 1 or 2 is binomial (n,p) with n=50 and p=3/10 hence the p-value is p = P [ X 5 ] where X is binomial (50,3/10), that is,
p = k = 0 5 ( 50 k ) ( 7 10 ) 50 k ( 3 10 ) k .

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