We know that if T is a sufficient statistic for theta then f(T) is a sufficient statistic for f(theta) if f(.) is a one -one function. But,what if f is not one one? For example, in case of Bernoulli (p) ,how to find the sufficient statistic for p(1−p)?

ajanlr

ajanlr

Answered question

2022-10-30

We know that if T is a sufficient statistic for θ then f ( T ) is a sufficient statistic for f ( θ ) if f ( . ) is a one -one function. But,what if f is not one one? For example, in case of Bernoulli ( p ) ,how to find the sufficient statistic for p ( 1 p )?

Answer & Explanation

namotanimfc

namotanimfc

Beginner2022-10-31Added 7 answers

If T is a sufficient statistic for θ, then
T is a sufficient statistic for f ( θ ) for any function f,
f ( T ) is a sufficient statistic for θ for any injective function f.
Since you want a sufficient statistic for f ( θ ), this function doesn’t need to be injective.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in College Statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?