Prove that if diam(G)=3 for a regular graph G, then d i a m ( <mrow class="MJX-Te

Mayra Berry

Mayra Berry

Answered question

2022-06-10

Prove that if diam(G)=3 for a regular graph G, then d i a m ( G ¯ ) = 2..
I know that without using regularity one can show that if d i a m ( G ) 3 , then  d i a m ( G ¯ ) 3. How do I use regularity to show that it must be exactly 2?

Answer & Explanation

Punktatsp

Punktatsp

Beginner2022-06-11Added 22 answers

Suppose G is a graph with diam(G)>2 and d i a m ( G ¯ ) > 2 ;; I will show that G is not regular.
More precisely, let x , y , v , w be vertices with d G ( x , y ) > 2 and d G ¯ ( v , w ) > 2 ;; I will show that deg ( v ) + deg ( w ) > deg ( x ) + deg ( y ) ,, the degrees being computed in G.
Clearly x , y , v , w are four distinct vertices, v w E ( G ) , and x y E ( G ¯ ) . Since d G ¯ ( v , w ) > 2 , at least one of the edges x v , x w is in E(G); without loss of generality, we assume that x v E ( G ) . It readily follows that y v E ( G ¯ ) ,   y w E ( G ) ,, and x w E ( G ¯ ) ..
Let S = V ( G ) { x , y , v , w } .. Let m be the number of edges (of G) between S and { v , w } ,, and let n be the number of edges between S and {x,y}. Then deg ( v ) + deg ( w ) = m + 4 ,, and deg ( x ) + deg ( y ) = n + 2.
Since each vertex in S is joined (by an edge of G) to at least one vertex in { v , w } and to at most one vertex in {x,y}, we have m n ;; it follows that
deg ( v ) + deg ( w ) = m + 4 > n + 2 = deg ( v ) + deg ( w ) .

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