Given equation is :
To solve this equation use Laplace transform. Apply Laplace transform on both sides:
The standard Laplace transform gives that
Let the Laplace transform of y(t) be Y(s)
Then the equation turns into:
Use the standard Laplace transform of
Now, apply the inverse Laplace transform on the obtained equation above.
Since the Laplace transform of y(t) is Y(s), inverse Laplace of Y(s) is y(t)
Then, the resultant equation is:
Therefore, the solution for the given equation is
The Laplace transform of the product of two functions is the product of the Laplace transforms of each given function. True or False
The Laplace transform of
1 degree on celsius scale is equal to
A) degree on fahrenheit scale
B) degree on fahrenheit scale
C) 1 degree on fahrenheit scale
D) 5 degree on fahrenheit scale
The Laplace transform of is A. B. C. D.
What is the Laplace transform of
Find the general solution of the given differential equation:
The rate at which a body cools is proportional to the difference in
temperature between the body and its surroundings. If a body in air
at 0℃ will cool from 200℃ 𝑡𝑜 100℃ in 40 minutes, how many more
minutes will it take the body to cool from 100℃ 𝑡𝑜 50℃ ?
A body falls from rest against a resistance proportional to the velocity at any instant. If the limiting velocity is 60fps and the body attains half that velocity in 1 second, find the initial velocity.
What's the correct way to go about computing the Inverse Laplace transform of this?
I Completed the square on the bottom but what do you do now?
How to find inverse Laplace transform of the following function?
I tried to use the definition: or the partial fraction expansion but I have not achieved results.
How do i find the lapalace transorm of this intergral using the convolution theorem?
How can I solve this differential equation? :
Find the inverse Laplace transform of
inverse laplace transform - with symbolic variables: